American Football
American Football games played on Sunday, 26 December 1993
United States of America: NFL
| Team | Score | | | Score | Team |
| Atlanta Falcons | 17 | | | 21 | Cincinnati Bengals |
| Cleveland Browns | 42 | | | 14 | Los Angeles Rams |
| Detroit Lions | 20 | | | 14 | Chicago Bears |
| Indianapolis Colts | 0 | | | 38 | New England Patriots |
| Kansas City Chiefs | 10 | | | 30 | Minnesota Vikings |
| Los Angeles Raiders | 0 | | | 28 | Green Bay Packers |
| New Orleans Saints | 26 | | | 37 | Philadelphia Eagles |
| New York Giants | 6 | | | 17 | Phoenix Cardinals |
| New York Jets | 14 | | | 16 | Buffalo Bills |
| Pittsburgh Steelers | 6 | | | 16 | Seattle Seahawks |
| Tampa Bay Buccaneers | 17 | | | 10 | Denver Broncos |
| Washington Redskins | 3 | | | 38 | Dallas Cowboys |
What else happened on Sunday, 26 December 1993?
Discover what the world looked like on the 26 dec 1993