American Football
American Football games played on Sunday, 26 December 1993
United States of America: NFL
Team | Score | | | Score | Team |
Atlanta Falcons | 17 | | | 21 | Cincinnati Bengals |
Cleveland Browns | 42 | | | 14 | Los Angeles Rams |
Detroit Lions | 20 | | | 14 | Chicago Bears |
Indianapolis Colts | 0 | | | 38 | New England Patriots |
Kansas City Chiefs | 10 | | | 30 | Minnesota Vikings |
Los Angeles Raiders | 0 | | | 28 | Green Bay Packers |
New Orleans Saints | 26 | | | 37 | Philadelphia Eagles |
New York Giants | 6 | | | 17 | Phoenix Cardinals |
New York Jets | 14 | | | 16 | Buffalo Bills |
Pittsburgh Steelers | 6 | | | 16 | Seattle Seahawks |
Tampa Bay Buccaneers | 17 | | | 10 | Denver Broncos |
Washington Redskins | 3 | | | 38 | Dallas Cowboys |
What else happened on Sunday, 26 December 1993?
Discover what the world looked like on the 26 dec 1993