American Football
American Football games played on Sunday, 28 November 1993
United States of America: NFL
| Team | Score | | | Score | Team |
| Buffalo Bills | 7 | | | 23 | Kansas City Chiefs |
| Cleveland Browns | 14 | | | 17 | Atlanta Falcons |
| Denver Broncos | 17 | | | 9 | Seattle Seahawks |
| Los Angeles Raiders | 10 | | | 16 | Cincinnati Bengals |
| New Orleans Saints | 17 | | | 14 | Minnesota Vikings |
| New York Jets | 6 | | | 0 | New England Patriots |
| Philadelphia Eagles | 17 | | | 14 | Washington Redskins |
| Phoenix Cardinals | 17 | | | 19 | New York Giants |
| Pittsburgh Steelers | 3 | | | 23 | Houston Oilers |
| San Francisco 49ers | 35 | | | 10 | Los Angeles Rams |
| Tampa Bay Buccaneers | 10 | | | 13 | Green Bay Packers |
What else happened on Sunday, 28 November 1993?
Discover what the world looked like on the 28 nov 1993